Program of Sum of Even Element of Array In C | Programmerdouts

Practice Program

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Program of Sum of even Element in an array.

Solution:

void main()
{
    int a[10],n,i;
    int sum_of_even = 0;

    printf("Enter the number of elements: ");
    scanf("%d",&n);

  //taking array elements as input.
    for(i=0;i<i++)
    {
        printf("\nEnter the Element: ");
        scanf("%d",&a[i]);
    }

    //printing the array elements
    printf("Array Elements are: \n");
    for(i=0;i<i++)
    {
        printf("%d\t",a[i]);

    }

  //CALCULATING THE SUM OF ODD AND EVEN ELEMENTS.
    for(i=0;i<i++)
    {
        if(a[i]%2 == 0)
        {
            sum_of_even = sum_of_even + a[i];
        }

    }


    printf("\nSum of all Even Numbers is %d",sum_of_even);


}

Output1

Enter the number of elements: 5

Enter the Element:1
Enter the Element:2
Enter the Element: 3
Enter the Element: 4
Enter the Element:5

Array Elements are:
1      2     3     4     5

Sum of all Even Numbers is 6

Output2

Enter the number of elements: 10

Enter the Element:1
Enter the Element:2
Enter the Element: 3
Enter the Element: 4
Enter the Element:5
Enter the Element:6
Enter the Element:7
Enter the Element: 8
Enter the Element: 9
Enter the Element:10

Array Elements are:
1      2     3     4     5     6      7     8     9     10

Sum of all Even Numbers is 30.

Output3

Enter the number of elements: 15

Enter the Element:1
Enter the Element:2
Enter the Element: 3
Enter the Element: 4
Enter the Element:5
Enter the Element:6
Enter the Element:7
Enter the Element: 8
Enter the Element: 9
Enter the Element:10
Enter the Element:11
Enter the Element:12
Enter the Element: 13
Enter the Element: 14
Enter the Element:15

Array Elements are:
1      2     3     4     5     6      7     8     9     10     11     12     13     14    15

Sum of all Even Numbers is 56.

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defining a function 'sum_of_even' which will return sum of all Even numbers.

int sum_of_even(int a[],int n)
{
     int sum_of_even = 0;
    int i;

     for(i=0;i<i++)
    {
        if(a[i]%2 == 0)
        {
            sum_of_even = sum_of_even + a[i];
        }

    }

return sum_of_even;


}

Using above define function 'sum_of_even()':

void main()
{
    int a[10] = {1,2,3,4,5};
    
    result = sum_of_even(a,5);
    
    printf("Sum of all even numbers are %d",result);
}

Output1

Sum of all even numbers are 6.

Using above define function 'sum_of_even()':

void main()
{
    int a[10] = {1,2,3,4,5,6,7,8,9,10};
    int result;
    result = sum_of_even(a,10);
    
    printf("Sum of all even numbers are %d",result);
}

Output2

Sum of all even numbers are 30.

Using above define function 'sum_of_even()':

void main()
{
    int a[10] = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15};
    int result;
    result = sum_of_even(a,15);
    
    printf("Sum of all even numbers are %d",result);
}

Output3

Sum of all even numbers are 54.

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