Practice Program






  • Program to Reverse a number.

    • Solution: through while loop 
    void main()
{
    int a,b=0,n;

    printf("Enter the number");
    scanf("%d",&n);

    while(n!=0)
    {  //when we number is modulo with 10
    // then give the last digit of that number
        a = n%10;
                    //at every iteration we are  assigning the current_value of b
                    //multiply by 10 and then adding the value of a and
        b = (b*10)+a; //assigning to the new value of b.

        n = n/10; //after setting up with new value of b then
                  //we are assigning the current value to n divide by 10 to
    }             //the the new value of n.

    printf("Reverse number is %d",b);
}

    Output1
    Enter the Number:321

    Reverse number is 123.
    Output2
    Enter the Number:3421

    Reverse number is 1243.
    Output3
    Enter the Number:456

    Reverse number is 654.




    Solution:from do-while loop 
    void main()
{
    int a,b=0,n;

    printf("Enter the number");
    scanf("%d",&n);

    do
    {  //when we number is modulo with 10
    // then give the last digit of that number
        a = n%10;
                    //at every iteration we are  assigning the current_value of b
                    //multiply by 10 and then adding the value of a and
        b = (b*10)+a; //assigning to the new value of b.

        n = n/10; //after setting up with new value of b then
                  //we are assigning the current value to n divide by 10 to
    }while(n!=0);             //the the new value of n.

    printf("Reverse number is %d",b);
}





    defining a function 'reverse_number' which will return the reverse number. 

    int reverse_number(int n)
{
    int a,b=0;


    while(n!=0)
    {  //when we number is modulo with 10
    // then give the last digit of that number
        a = n%10;
                    //at every iteration we are  assigning the current_value of b
                    //multiply by 10 and then adding the value of a and
        b = (b*10)+a; //assigning to the new value of b.

        n = n/10; //after setting up with new value of b then
                  //we are assigning the current value to n divide by 10 to
    }             // the new value of n.

    return b;
}

    Using above define function 'reverse_number': 
    void main()
{
    int n,result;

    printf("Enter the  Number: ");
    scanf("%d",&n);


    //calling function
    result = reverse_number(n);

printf("Rverse number is %d",result);

}

    Output1
    Enter the Number:321

    Reverse number is 123.

    Using above define function 'reverse_number': 
    void main()
{
    int n,result;

    printf("Enter the  Number: ");
    scanf("%d",&n);


    //calling function
    result = reverse_number(n);

printf("Sum of digits is %d",result);

}

    Output2
    Enter the Number:3421

    Reverse number is 1243.

    Using above define function 'reverse_number': 
    void main()
{
    int n,result;

    printf("Enter the  Number: ");
    scanf("%d",&n);


    //calling function
    result = reverse_number(n);

printf("Sum of digits is %d",result);

}

    Output3
    Enter the Number:456

    Reverse number is 654.