Program of printing n natural number in reverrse order | In C

Practice Program

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Program of printing first 'n' natural numbers   in reverse order.

Solution:through for loop

void main()
{
    int n,i;

    printf("How many natural number you  want to print: ");
    scanf("%d",&n);


    printf("First %d natural numbers are:\n",n);
    for(i=n; i>0; i--)
    {
        printf("%d\t",i);
    }


}

Output1

How many natural number you want to print: 5

natural numbers In reverse order are:
5    4    3    2     1

Output2

How many natural number you want to print: 10

Natural numbers in reverse are :
10    9    8    7    6     5    4    3    2     1

Output3

How many natural number you want to print: 15

Natural numbers in reverse order are:
15    14    13    12    11    10    9    8    7    6     5    4    3    2     1

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Solution : through while loop

void main()
{
    int n,i;

    printf("How many natural number you  want to print: ");
    scanf("%d",&n);

i = n
    printf("\nNatural numbers in reverse order are:");
    while(i>0)
    {
        printf("%d\t",i);
        i--;
    }


}

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Solution:from do-while loop

void main()
{
    int n,i;

    printf("How many natural number you  want to print: ");
    scanf("%d",&n);

i = n
    printf("Natural numbers in reverse order are:\n");
    do
    {
        printf("%d\t",i);
        i--;
    }
     while(i>0);

}

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