Program of Factors with explanation | In C

Practice Program

---

Program Of Factors of a Numbers.

A factor of an integer n is an integer which can be multiplied by some integer to produce n.

For every number , 1 and itself are one of the factors of n.

If 10 is an integer then it's factors are = 1,2,5,10, for 20 ,factors are = 1,2,4,5,10,20

We will write a program to display the factors of a number.

Solution:through for loop

void main()
{
    int i,n;

    printf("Enter the number:");
    scanf("%d",&n);


 //As you know 1 is factor of every number ,
 
 printf("Factors of %d are:",n);
 //so we are printing it
    printf("%d\t",1);


    for(i=2;i<i++)
    {
        if(n%i == 0)//for every value of i we are checking that,
          printf("%d\t",i); //Is n is divisible by i
    }              //so,if it is divisible by i then ,i
                   //is the one of the factor of
                      //n and we are printing it.
    printf("%d",n);
    //As you know every element is divisible by itself
    //So we are printing the value of 'n' as one of the
     //factor of 'n'
}

Output1

Enter the number:20

Factors of 20 are:: 1       2        4        5        10     20

Output2

Enter the number:10

Factors of 10 are:
1       2        5        10

Output3

Enter the number:30

Factors of 30 are:
1      2       3        5        6        10     15    30

---

Solution:from while loops

void main()
{
    int i,n;

    printf("Enter the number:");
    scanf("%d",&n);


 //As you know 1 is factor of every number ,
 //so we are printing it
    printf("%d\t",1);

    i=2;
    while(i<n)
    {
        if(n%i == 0)//for every value of i we are checking that,
          printf("%d\t",i); //Is n is divisible by i
     i++;              //so,if it is divisible by i then ,i
    }             //is the one of the factor of
                      //n and we are printing it.
    printf("%d",n);
    //As you know every element is divisible by itself
    //So we are printing the value of 'n' as one of the
     //factor of 'n'
}

Solution:from do-while loops

void main()
{
    int i,n;

    printf("Enter the number:");
    scanf("%d",&n);


 //As you know 1 is factor of every number ,
 //so we are printing it
    printf("%d\t",1);

    i=2;
    do
    {
        if(n%i == 0)//for every value of i we are checking that,
          printf("%d\t",i); //Is n is divisible by i
     i++;              //so,if it is divisible by i then ,i
    } while(i<n);             //is the one of the factor of
                      //n and we are printing it.
    printf("%d",n);
    //As you know every element is divisible by itself
    //So we are printing the value of 'n' as one of the
     //factor of 'n'
}

---

defining a function 'give_factor()' which will print factors of number.

void  give_factor(n)
{ int i;
    //As you know 1 is factor of every number ,
 //so we are printing it
    printf("%d\t",1);

    i=2;
    while(i<n)
    {
        if(n%i == 0)//for every value of i we are checking that,
          printf("%d\t",i); //Is n is divisible by i
     i++;              //so,if it is divisible by i then ,i
    }             //is the one of the factor of
                      //n and we are printing it.
    printf("%d",n);
    //As you know every element is divisible by itself
    //So we are printing the value of 'n' as one of the
     //factor of 'n'
}

Using above define function 'give_factor()':

void main()
{
    int i,n;

    printf("Enter the number:");
    scanf("%d",&n);
   printf(" Factors of %d are:",n);
    //calling function 
    give_factor(n);  //actual parameters.

 
}

Output1

Enter the number:20

Factors of 20 are: 1       2        4        5        10     20

Using above define function 'give_factor()':

void main()
{
    int i,n;

    printf("Enter the number:");
    scanf("%d",&n);
   printf(" Factors of %d are:",n);
    //calling function 
    give_factor(n);  //actual parameters.

 
}

Output2

Enter the number:10

Factors of 10 are:
1       2        5        10

Using above define function 'give_factor()':

void main()
{
    int i,n;

    printf("Enter the number:");
    scanf("%d",&n);
   
    printf(" Factors of %d are:",n);
    //calling function 
   give_factor(n);  //actual parameters.

 
}

Output2

Enter the number:30

Factors of 30 are:
1      2       3        5        6        10     15    30

---

---

---