Practice Program






  • Program of factorial of a numbers

    • Solution: through while loop 
    void main()
{
    int a,n,count=0;

    printf("Enter the Number: ");
    scanf("%d",&n);


    while(n!=0)
    {
        a = n%10;//as modulo operator gives
        count++;  //last digit of number
                  //when we modulo number with 10.
        n = n/10;
             //when we divide a number with 10
             //then it removes the last digit from 
            //the number
    }

    printf("There are %d digit.",count);

}

    Output1
    Enter the Number:321

    There are 2 digit.
    Output2
    Enter the Number:3421

    There are 4 digit.
    Output3
    Enter the Number:3214561

    There are 7 digit.




    Solution: from do-while loop 
    void main()
{
    int a,n,count=0;

    printf("Enter the Power: ");
    scanf("%d",&n);


    do
    {
        a = n%10;//as modulo operator gives
        count++;  //last digit of number
                  //when we modulo number with 10.
        n = n/10;
             //when we divide a number with 10
             //then it removes the last digit from
            //the number
    } while(n!=0);

    printf("There are %d digit.",count);

}





    defining a function 'count_digit' which will return number of digit. 

    int count_digit(int n)
{
    int a,count = 0;
     while(n!=0)
    {
        a = n%10;//as modulo operator gives
        count++;  //last digit of number
                  //when we modulo number with 10.
        n = n/10;
             //when we divide a number with 10
             //then it removes the last digit from
            //the number
    }

    return count;
}

    Using above define function 'count_digit': 
    void main()
{
    int n,count;

    printf("Enter the Power: ");
    scanf("%d",&n);


   count = count_digit(n);

    printf("There are %d digit.",count);

}

    Output1
    Enter the Number:321

    There are 2 digit.

    Using above define function 'count_digit': 
    void main()
{
    int n,count;

    printf("Enter the Power: ");
    scanf("%d",&n);


   count = count_digit(n);

    printf("There are %d digit.",count);

}

    Output2
    Enter the Number:3421

    There are 4 digit.

    Using above define function 'count_digit': 
    void main()
{
    int n,count;

    printf("Enter the Power: ");
    scanf("%d",&n);


   count = count_digit(n);

    printf("There are %d digit.",count);

}

    Output3
    Enter the Number:3214561

    There are 7 digit.