Program of checking number is palindrome or not | In C

Practice Program

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Program Of Reversing a number.

Solution:through while loop

void main()
{
    int a,b=0,n,m;

    printf("Enter the number");
    scanf("%d",&m);

    n = m;
     while(n!=0)
    {  //when we number is modulo with 10
    // then give the last digit of that number
        a = n%10;
                    //at every iteration we are  assigning the current_value of b
                    //multiply by 10 and then adding the value of a and
        b = (b*10)+a; //assigning to the new value of b.

        n = n/10; //after setting up with new value of b then
                  //we are assigning the current value to n divide by 10 to
    }            //the the new value of n.

    if(b == m) //if we value of b and m are same
    {   //then we will print number is palindrome,
        printf("Number is palindrome"); //otherwise we will print not palindrome
    }
    else
        printf("Number is Not Palindrome");
}

Output1

Enter the Number:321

Number is Not Palindrome

Output2

Enter the Number:101

Number is Palindrome

Output3

Enter the Number:456

Number is Not Palindrome

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Solution:from do-while loop

void main()
{
    int a,b=0,n,m;

    printf("Enter the number");
    scanf("%d",&m);

    n = m;
     do
    {  //when we number is modulo with 10
    // then give the last digit of that number
        a = n%10;
                    //at every iteration we are  assigning the current_value of b
                    //multiply by 10 and then adding the value of a and
        b = (b*10)+a; //assigning to the new value of b.

        n = n/10; //after setting up with new value of b then
                  //we are assigning the current value to n divide by 10 to
    }while(n!=0);            //the the new value of n.

    if(b == m) //if we value of b and m are same
    {   //then we will print number is palindrome,
        printf("Number is palindrome"); //otherwise we will print not palindrome
    }
    else
        printf("Number is Not Palindrome");
}

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defining a function 'is_palindrome' which will check a number is palindrome or not.

int is_palindrome(int m) //formal parameters
{
     int a,b=0,n;
     n = m;//assigning the value of m
             //to variable n.
             //because further we will need m.
    while(n!=0)
    {  //when we number is modulo with 10
    // then give the last digit of that number
        a = n%10;
                    //at every iteration we are  assigning the current_value of b
                    //multiply by 10 and then adding the value of a and
        b = (b*10)+a; //assigning to the new value of b.

        n = n/10; //after setting up with new value of b then
                  //we are assigning the current value to n divide by 10 to
    }             //the the new value of n.

    if(m == b)//if value in variable m and b are same
      return 1;  //then we will return 1,
    else         // it means the given numbers is palindrome number
      return 0;

      // we will return 0,if number is not palindrome.
}

Using above define function 'is_palindrome':

void main()

{
    int n,result;

    printf("Enter the Number");
    scanf("%d",&n);

    //calling function.
    result = is_palindrome(n);//actual parameter.

    if(result == 1)//if 'is_palindrome()' will return 1,
    {            // then number is palindrome,otherwise not
        printf("Number is Palindrome");
    }
    else
        printf("Number is Not Palindrome");
}

Output1

Enter the Number:101

Number is Palindrome

Using above define function 'is_palindrome':

void main()

{
    int n,result;

    printf("Enter the Number");
    scanf("%d",&n);

    //calling function.
    result = is_palindrome(n);//actual parameter.

    if(result == 1)//if 'is_palindrome()' will return 1,
    {            // then number is palindrome,otherwise not
        printf("Number is Palindrome");
    }
    else
        printf("Number is Not Palindrome");
}

Output2

Enter the Number:3421

Number is Not Palindrome.

Using above define function 'is_palindrome':

void main()

{
    int n,result;

    printf("Enter the Number");
    scanf("%d",&n);

    //calling function.
    result = is_palindrome(n);//actual parameter.

    if(result == 1)//if 'is_palindrome()' will return 1,
    {            // then number is palindrome,otherwise not
        printf("Number is Palindrome");
    }
    else
        printf("Number is Not Palindrome");
}

Output3

Enter the Number:456

Number is Not Palindrome

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