Program of calculating sum of square of n numbers | In C

Practice Program

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Program of calculating sum of square of n natural numbers

Solution: through for loop

void main()
{
    int n,i,sum = 0;;
    printf("Sum of how many numbers: ");
    scanf("%d",&n);
    
    //at every iteration we are assigning 
    //(current_value + (i*i) ) to new value of sum. 
    for(i=1;i<=n;i++)
    {
        sum = sum+(i*i);
    }
    
    
    printf("Sum of square of  first %d natural numbers are %d",n,sum);
   

}

Output1

Sum of how many numbers:5

Sum of Square of first 5 natural numbers are 55.

Output2

Sum of how many numbers:10

Sum of Square of first 10 natural numbers are 385.

Output3

Sum of how many numbers:15

Sum of Square of first 15 natural numbers are 1240.

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Solution : through while loop

void main()
{
    int n,i,sum = 0;;
    printf("Sum of how many numbers: ");
    scanf("%d",&n);
      i=1;
    //at every iteration we are assigning
    //(current_value + i ) to new value of sum.
    while(i<=n)
    {
         sum = sum+(i*i);
        i++;
    }


    printf("Sum of square of  first %d natural numbers are %d",n,sum);


}

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Solution: from do-while loop

void main()
{
    int n,i,sum = 0;;
    printf("Sum of how many numbers: ");
    scanf("%d",&n);
      i=1;
    //at every iteration we are assigning
    //(current_value + i ) to new value of sum.
    do
    {
        sum = sum+(i*i);
        i++;
    }while(i<=n)


    printf("Sum of square of first %d natural numbers are %d",n,sum);


}

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defining a function 'sum_of_square' which will return sum of square of n numbers.

int sum_of_square(int n)
{
    int i,sum=0;

     //at every iteration we are assigning
    //(current_value + (i*i) ) to new value of sum.
    for(i=1; i<=n; i++)
    {
         sum = sum+(i*i);
    }
    return sum;
}

Using above define function 'sum_of_square':

void main()
{
    int n,result;
    printf("How many  numbers of sum you want: ");
    scanf("%d",&n);


   result  = sum_of_square(5);


   printf("Sum of square of first %d numbers are %d",n,result);



}

Output1

Sum of how many numbers:5

Sum of square of first 5 natural numbers are 55.

Using above define function 'sum_of_square':

void main()
{
    int n,result;
    printf("How many  numbers of sum you want: ");
    scanf("%d",&n);


   result  =sum_of_square(10);


   printf("Sum of square of first %d numbers are %d",n,result);



}

Output2

Sum of how many numbers:10

Sum of square of first 10 natural numbers are 385.

Using above define function 'sum_of_square':

void main()
{
    int n,result;
    printf("How many  numbers of sum you want: ");
    scanf("%d",&n);


   result  = sum_of_square(15);

 
   printf("Sum of square of first %d numbers are %d",n,result);



}

Output3

Sum of how many numbers:15

Sum of square of first 15 natural numbers are 1240.

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